Hasil Perhitungan Range IP Address Menggunakan Sistem VLSM

1.) IP Address awal = 192.222.0.0/23, tentukan range networknya jika masing-masing subnet-nya mempunyai:
A= 54 PC
B= 20 PC
C= 120 PC
D= 44 PC
E= 28 PC
 
JAWAB:
I.
  a. 54+2 = 56 IP Address = 64   mask = /26 = 255.255.255.192
  b. 20+2 = 22 IP Address = 32   mask = /27 = 255.255.255.224
  c. 120+2 =  122 IP Address = 128   mask = /25 = 255.255.255.128
  d. 44+2 = 46 IP Address = 64   mask = /26 = 255.255.255.192
  e. 28+2 = 30 IP Address = 32   mask = /27 = 255.255.255.224
                            Jumlah   = 320
II.
  c = 192.222.0.0/25-192.222.0.127/25
  a = 192.222.0.128/26-192.222.0.191/26
  d = 192.222.0.192/26-192.222.0.255/26
  e = 192.222.1.0/27-192.222.1.31/27
  b = 192.222.1.32/27-192.222.1.63/27
sisa = 192.222.1.64-192.222.1.255 = 192 host, masih dapat dibuat network dengan syarat maskingnya harus lebih kecil dari range terkecil/terakhir.

2.) IP Address awal = 172.16.16.0/23, tentukan range networknya jika masing-masing subnet-nya mempunyai:
A= 10 PC
B= 28 PC
C= 15 PC
D= 60 PC
E= 210 PC
 

JAWAB:
I.
  a. 10+2 = 12 IP Address = 16   mask = /28 = 255.255.255.240
  b. 28+2 = 30 IP Address = 32   mask = /27 = 255.255.255.224
  c. 15+2 =  17 IP Address = 32   mask = /27 = 255.255.255.224
  d. 60+2 = 62 IP Address = 64   mask = /26 = 255.255.255.192
  e. 210+2 = 212 IP Address = 256   mask = /24 = 255.255.255.0
                            Jumlah   = 400

II.
  e = 172.16.16.0/24-172.16.16.255/24
  d = 172.16.17.0/26-172.16.17.63/26
  b = 172.16.17.64/27-172.16.17.95/27
  c = 172.16.17.96/27-172.16.17.127/27
  a = 172.16.17.128/28-172.16.17.143/28
sisa = 172.16.1.144-172.16.17.255 = 112 host, masih dapat dibuat network dengan syarat maskingnya harus lebih kecil dari range terkecil/terakhir.


3.) IP Address awal = 168.16.64.0/22, tentukan range networknya jika masing-masing subnet-nya mempunyai:
A= 10 PC
B= 15 PC
C= 31 PC
D= 44 PC
E= 50 PC
F= 100 PC
G= 120 PC
H= 210 PC
 

JAWAB:
I.
  a. 10+2 = 12 IP Address = 16   mask = /28 = 255.255.255.240
  b. 15+2 = 17 IP Address = 32   mask = /27 = 255.255.255.224
  c. 31+2 =  33 IP Address = 64   mask = /26 = 255.255.255.192
  d. 44+2 = 46 IP Address = 64   mask = /26 = 255.255.255.192
  e. 50+2 = 52 IP Address = 64   mask = /26 = 255.255.255.192
  f. 100+2= 102 IP Address = 128   mask = /25 = 255.255.255.128
  g. 120+2= 122 IP Address = 128   mask = /25 = 255.255.255.128
  h. 210+2= 212 IP Address = 256   mask = /24 = 255.255.255.0
                            Jumlah   = 752

II.
  h = 168.16.64.0/24-168.16.64.255/24
  g = 168.16.65.0/25-168.16.65.127/25
  f = 168.16.65.128/25-168.16.65.255/25
  e = 168.16.66.0/26-168.16.66.63/26
  d = 168.16.66.64/26-168.16.66.127/26
  c = 168.16.66.128/26-168.16.66.191/26
  b = 168.16.66.192/27-168.16.66.223/27
  a = 168.16.66.224/27-168.16.66.255/27
sisa = 168.16.67.0-168.16.67.255 = 255 host, masih dapat dibuat network dengan syarat maskingnya harus lebih kecil dari range terkecil/terakhir.

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