Hasil Perhitungan Range IP Address Menggunakan sistem CIDR

smartdanic No comments
1) Diketahui Network Address awal = 182.172.24.0/22 dengan jumlah subnet 6 buah tentukan jumlah masing-masing host dalam subnet
I. Tentukan range network awal
 182.172.24.0-182.172.27.255
 Jumlah host awal = 32-22=2pangkat10=1024

II. Tentukan panjang tiap subnet
Panjang Subnet = Jumlah host awal/Subnet
                         = 1024/8 = 128(2pangkat7)
Masking = 32-7 = /25

III. Alokasi tiap Subnet
182.172.24.0/25-182.172.24.127/25
182.172.24.127/25-182.172.24.255/25
182.172.25.0/25-182.172.25.127/25
182.172.25.127/25-182.172.25.255/25
182.172.26.0/25-182.172.26.127/25
182.172.26.127/25-182.172.26.255/25
182.172.27.0/25-182.172.27.127/25
182.172.27.127/25-182.172.27.255/25


2) Diketahui Network Address awal = 192.168.46.0/23 dengan jumlah subnet 4 buah tentukan jumlah masing-masing host dalam subnet
I. Tentukan range network awal
 192.168.46.0-192.168.47.255
 Jumlah host awal = 32-23=2pangkat9=512

II. Tentukan panjang tiap subnet
Panjang Subnet = Jumlah host awal/Subnet
                         = 512/4 = 128(2pangkat7)
Masking = 32-7 = /25

III. Alokasi tiap Subnet
192.168.46.0/25-192.168.46.127/25
192.168.46.128/25-192.168.46.255/25
192.168.47.0/25-192.168.47.127/25
192.168.47.128/25-192.168.47.255/25

 3) Diketahui Network Address awal = 172.171.24.0/21 dengan jumlah subnet 8 buah tentukan jumlah masing-masing host dalam subnet
I. Tentukan range network awal
 172.171.24.0-172.171.31.255
 Jumlah host awal = 32-21=2pangkat11=2048

II. Tentukan panjang tiap subnet
Panjang Subnet = Jumlah host awal/Subnet
                         = 2048/8 = 256(2pangkat8)
Masking = 32-8 = /24

III. Alokasi tiap Subnet
172.171.24.0/24-172.171.24.255/24
172.171.25.0/24-172.171.25.255/24
172.171.26.0/24-172.171.26.255/24
172.171.27.0/24-172.171.27.255/24
172.171.28.0/24-172.171.28.255/24
172.171.29.0/24-172.171.29.255/24
172.171.30.0/24-172.171.30.255/24
172.171.31.0/24-172.171.31.255/24



4) Diketahui Network Address awal = 172.171.32.0/19 dengan jumlah host dalam satu subnet = 254 buah tentukan jumlah subnet yang diperlukan

I. Tentukan range network awal
 172.171.32.0-172.171.63.255
 Jumlah host awal = 32-19=2pangkat13=8192

II. Tentukan panjang tiap subnet
Panjang Subnet = Jumlah host awal/jumlah host satu subnet
                         = 8192/256 = 32(2pangkat8)
Masking = 32-8 = /24

III. Alokasi tiap Subnet
172.171.32.0/24-172.171.32.255/24
172.171.33.0/24-172.171.33.255/24
172.171.34.0/24-172.171.34.255/24
172.171.35.0/24-172.171.35.255/24
172.171.36.0/24-172.171.36.255/24
172.171.37.0/24-172.171.37.255/24
172.171.38.0/24-172.171.38.255/24
172.171.39.0/24-172.171.39.255/24
172.171.40.0/24-172.171.40.255/24
172.171.41.0/24-172.171.41.255/24
172.171.42.0/24-172.171.42.255/24
172.171.43.0/24-172.171.43.255/24
172.171.44.0/24-172.171.44.255/24
172.171.45.0/24-172.171.45.255/24
172.171.46.0/24-172.171.46.255/24
172.171.47.0/24-172.171.47.255/24
172.171.48.0/24-172.171.48.255/24
172.171.49.0/24-172.171.49.255/24
172.171.50.0/24-172.171.50.255/24
172.171.51.0/24-172.171.51.255/24
172.171.52.0/24-172.171.52.255/24
172.171.53.0/24-172.171.53.255/24
172.171.54.0/24-172.171.54.255/24
172.171.55.0/24-172.171.55.255/24
172.171.56.0/24-172.171.56.255/24
172.171.57.0/24-172.171.57.255/24
172.171.58.0/24-172.171.58.255/24
172.171.59.0/24-172.171.59.255/24
172.171.60.0/24-172.171.60.255/24
172.171.61.0/24-172.171.61.255/24
172.171.62.0/24-172.171.62.255/24
172.171.63.0/24-172.171.63.255/24


5) Diketahui Network Address awal = 172.171.128.0/17 dengan jumlah host dalam satu subnet = 1000 buah tentukan jumlah subnet yang diperlukan


I. Tentukan range network awal
 172.171.128.0-172.171.255.255
 Jumlah host awal = 32-17=2pangkat15=32768

II. Tentukan panjang tiap subnet
Panjang Subnet = Jumlah host awal/jumlah host satu subnet

                         = 32768/1024 = 32(2pangkat8)
Masking = 32-10 = /22

III. Alokasi tiap Subnet

172.171.128.0/22-172.171.131.255/22
172.171.132.0/22-172.171.135.255/22
172.171.136.0/22-172.171.139.255/22
172.171.140.0/22-172.171.143.255/22
172.171.144.0/22-172.171.147.255/22
172.171.148.0/22-172.171.151.255/22
172.171.152.0/22-172.171.155.255/22
172.171.156.0/22-172.171.159.255/22
172.171.160.0/22-172.171.163.255/22
172.171.164.0/22-172.171.167.255/22
172.171.168.0/22-172.171.171.255/22
172.171.172.0/22-172.171.175.255/22
172.171.176.0/22-172.171.179.255/22
172.171.180.0/22-172.171.183.255/22
172.171.184.0/22-172.171.187.255/22
172.171.188.0/22-172.171.191.255/22
172.171.192.0/22-172.171.195.255/22
172.171.196.0/22-172.171.199.255/22
172.171.200.0/22-172.171.203.255/22
172.171.204.0/22-172.171.207.255/22
172.171.208.0/22-172.171.211.255/22
172.171.212.0/22-172.171.215.255/22
172.171.216.0/22-172.171.219.255/22
172.171.220.0/22-172.171.223.255/22
172.171.224.0/22-172.171.227.255/22
172.171.228.0/22-172.171.231.255/22
172.171.232.0/22-172.171.235.255/22
172.171.236.0/22-172.171.239.255/22
172.171.240.0/22-172.171.243.255/22
172.171.244.0/22-172.171.247.255/22
172.171.248.0/22-172.171.251.255/22
172.171.252.0/22-172.171.255.255/22
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